Looking at the subnet mask, ipaddress 192.168.3.47/28 is one of 16 addresses within that subnet (32-28 = 4, 2^4 = 16). For any subnet, the ipaddress with all 1's within the subnet is the broadcast ip address which you use in order to send a packet to every attached device within that subnet (See RFC 919). Now let's look at the binary representation of the last octet 47 which in binary is 00101111. Notice that the last 4 bits are all ones. So the problem is that IP address 192.168.3.47 is the broadcast address for the subnet. And anything that's intended on getting to that specific host is being sent to (and responded by) every attached host to that subnet.
