The first equation is ,
[tex] 4x+16y=12 [/tex]
First we need to solve this equation for y , and for that we need to subtract 4x from both sides, that is
[tex] 16y = 12-4x [/tex]
Now we need to get rid of 16, and for that we have to divide both sides by 16, that is
[tex] y= \frac{3}{4}-\frac{1}{4} x [/tex]
[tex] y= -\frac{1}{4} x+\frac{3}{4} [/tex]
And the second equation is
[tex] \\ y= -\frac{1}{4} x+\frac{9}{12} \\
[/tex]
And on simplifying we will get
[tex] y= -\frac{1}{4} x+\frac{3}{4} [/tex]
Which is same as the firrst equation. And in that case, there are infinite or many solutions .
