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The equation for the complete combustion of methane is ch4(g) + 2o2(g) → co2(g) + 2h2o(l) to calculate the number of grams of co2 produced by the reaction of 29.5 g of ch4 with o2, the first conversion factor to use is

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Dejanras
Answer is: 1 mol CH₄/16 g CH₄.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 29,5 g.
M(CH₄) = 1·12 g/mol + 4·1 g/mol = 16 g/mol.
n(CH₄) = m(CH₄) ÷ M(CH₄).
n(CH₄) = 29,5 g ÷ 16 g/mol
n(CH₄) = 1,84 mol.
from reaction: n(CH₄) = n(CO₂).
n(CO₂) = 1,84 mol.
m(CO₂) = 1,84 mol · 44 ··/mol.
m(CO₂) = 81 g.
n - amount of substance.

Yna9141
To determine the number or amount of carbon dioxide produced from the equation, we have to note from the given chemical reaction that the ratios of the moles of the participating reactants and the resulting products will be obtained.

The first step to answering this item is to determine the number of moles of CH4 by dividing the given amount in grams by the molar mass. Molar mass of methane, CH4, is equal to 16 g/mol.

The first conversion factor is therefore is 16 g/mol. 

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