Respuesta :
t= outside temp
-109.3= t-184.9
add 184.9 to each side
t=75.6
it is 75.6 degrees F outside
-109.3= t-184.9
add 184.9 to each side
t=75.6
it is 75.6 degrees F outside
Answer:
An equation : −109.3°F = Outside temperature -184.9°F.
Outside temperature = 75 .6°F.
Step-by-step explanation:
Given : The temperature of dry ice is −109.3°F. This is 184.9°F less than the outside temperature.
To find : Write and solve an equation to find the outside temperature t (in degrees Fahrenheit).
Solution : We have given
Temperature of dry ice = −109.3°F.
Let the outside temperature = T
According to question :
Dry ice temperature is 184.9°F less than outside temp.
−109.3°F = Outside temperature -184.9°F.
On adding both sides by 184.9
Outsides temperature = −109.3°F + 184.9°F
Outside temperature = 75 .6°F.
Therefore, An equation : −109.3°F = Outside temperature -184.9°F.
Outside temperature = 75 .6°F.