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As 390 g of hot milk cools in a mug it transfers 30 000 j of heat to the environment. whats is the temperature change of the milk? Specific heat of the milk is 3.9 j.g

Respuesta :

You have to use the specific heat equation. 

Q = cmΔT where Q is the energy, c is specific heat, m is mass, and ΔT is change in temp.

So we can substitute our variables into the equation.

30000J = (390g)(3.9J*g/C)ΔT

Solving for ΔT, we get:

30000J/[(390g)*(3.9J*g/C) = ΔT

ΔT = 19.72386588C

I'm assuming the temperature is C, since it was not specified.

Hope this helps!

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