contestada

What is the equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is y=54x−2 ? Enter your answer in the box.

Respuesta :

texaschic101
y = 5/4x - 2....the slope here is 5/4. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal slope, u take ur original slope, flip it, and change the sign. So we have 5/4.....flip it an it becomes 4/5...change the sign and it becomes - 4/5. So ur perpendicular line will have a slope of -4/5.

y = mx + b
slope(m) = -4/5
(10,5)...x = 10 and y = 5
now sub into the formula and find b, the y int
5 = -4/5(10) + b
5 = -40/5 + b
5 = -8 + b
5 + 8 = b
13 = b
so ur perpendicular equation is : y = -4/5x + 13 <===

The equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is (y = 5/4x − 2) is (5y + 4x = 65).

Given :

A line passes through the point (10,5) and is perpendicular to the line whose equation is y=5/4x−2.

The following steps can be used in order to determine the equation of a line that passes through the point (10, 5) and are perpendicular to the line whose equation is (y = 5/4x − 2):

Step 1 - Remember that when two lines are perpendicular to each other then their slopes are:

mm' = -1

Step 2 - So the slope of the line which is perpendicular to the line (y = 5/4x − 2) is:

[tex]\rm \dfrac{5}{4}m'=-1[/tex]

[tex]\rm m' = -\dfrac{4}{5}[/tex]

Step 3 - So, the equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is (y = 5/4x − 2) is:

[tex](y - 5)=-\dfrac{4}{5}(x-10)[/tex]

5y - 25 = -4x + 40

5y + 4x = 65

For more information, refer to the link given below:

https://brainly.com/question/2263981