Answer:
[tex] \bigtriangleup DPL\sim \bigtriangleup QAZ[/tex]
Step-by-step explanation:
In [tex] \bigtriangleup DPL and \bigtriangleup QAZ [/tex]
[tex] \frac{DL}{QZ}= \frac{25}{10} = \frac{5}{2} [/tex]
[tex] \frac{LP}{ZA} =\frac {55}{22} =\frac{5}{2}[/tex]
Therefore, [tex] \frac{DL}{QZ} = \frac {LP}{ZA} = \frac{5}{2} [/tex]
Also, from figure [tex] \angle DLP =\angle QZA [/tex]
By SAS property of similarity of triangles
[tex] \bigtriangleup DPL\sim \bigtriangleup QAZ [/tex]
