contestada

what is an equation of the line, in point slope form, that passes through the given point and has the given slope? point: (11/3); slope: 4/11

Respuesta :

y-3=4/11(x-11). Doing a problem like this is mostly memorizing point slope formula, by knowing y-y2=m(x-x1) you can just "plug" in 3 as your y1 and 11 as your x1 then finally 4/11 as your slope being y-3=4/11(x-11)
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ANSWER

The required equation is,

[tex]y - 3 = \frac{4}{11} (x - 11)[/tex]



EXPLANATION

The point given to us is,

[tex](11,3)[/tex]
and the slope is
[tex]m = \frac{4}{11} [/tex]


We apply the point slope formula which is given as follows,

[tex]y-y_1=m(x-x_1)[/tex]

We substitute the given point and the slope into the formula to obtain,

[tex]y - 3 = \frac{4}{11} (x - 11)[/tex]
This is the equation of the given line in the point-slope form.

No need to simplify because it says point-slope form.



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