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Answer is: in 3.36 L of oxygen gas there is 0,15 mol (6·10²²) molecules of oxygen. 
V(O₂) = 3,36 L.
Vm(O₂) = 22,4 L/mol.
n(O₂) = V(O₂) ÷ Vm(O₂).
n(O₂) = 3,36 L ÷ 22,4 L/mol.
n(O₂) = 0,15 mol.
N(O₂) = n(O₂) · Na.
N(O₂) = 0,15 mol · 6·10²³ 1/mol.
N(O₂)  = 9 · 10 ²².
n - amount of substance.
Na - Avogadro number.

Mass is both a property of a physical body and a measure of its resistance to acceleration when a net force is applied.

A standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles is called a mole.

According to the question, the formula we will use is as follows:-

To find the mole:- [tex]n= \frac{Volume}{22.4}[/tex]

Where V denotes the volume. Therefore, the mole required is [tex]9 * 10^2^2[/tex]

Hence,[tex]n= \frac{3.36}{22.4}[/tex]

= 0.15moles

For more information, refer to the link:-

https://brainly.com/question/20486415

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