[tex] \frac{x-7}{x+4} / \frac{x}{x+3} = \frac{x-7}{x+4} * \frac{x+3}{x} = \frac{(x-7)(x+3)}{(x+4)(x)} [/tex] Remember that dividing by a fraction is the same as multiplying by the reciprocal (or the reverse) of the fraction on the bottom. A restriction on the domain means that x can not be that value. This occurs when the denominator is zero. If (x+4) = 0 or x = o then the denominator will be zero so the restrictions are x = -4,0. The answer is c.
