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Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.

Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work.

Respuesta :

2x + 3y = 1,470
 Change the equation to slope-intercept form
 y = -(2/3)x + 490
 the slope
 m=
-(2/3)
 y-intercept 
 for x=0 ---> y=490

Answer:

The slope of the line is [tex]-\frac{2}{3}[/tex] and y-intercept is 490.

Step-by-step explanation:

The slope intercept form of a line is

[tex]y=mx+b[/tex]               .... (1)

where, m is slope and n is y-intercept.

The given equation is

[tex]2x+3y=1470[/tex]

where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.

Convert the given equation in slope intercept form.

Subtract 2x from both sides.

[tex]3y=-2x+1470[/tex]

Divide both sides by 3.

[tex]y=\frac{-2x+1470}{3}[/tex]

[tex]y=-\frac{2}{3}x+490[/tex]            .... (2)

On comparing (1) and (2) we get

[tex]m=-\frac{2}{3}[/tex]

[tex]b=490[/tex]

Therefore, the slope of the line is [tex]-\frac{2}{3}[/tex] and y-intercept is 490.