Answer: [tex]16a^2c[/tex]
Step-by-step explanation:
Given division problem: [tex]48a^3bc^2\div48a^3bc^2[/tex]
It can be written as :
[tex]\frac{48a^3bc^2}{3abc}[/tex]
Since, [tex]48=3\times16[/tex]
Divide 3 from numerator and denominator we get,
[tex]\frac{16a^3bc^2}{abc}[/tex]
The division law of exponent says that
[tex]\frac{a^m}{a^n}=a^{m-n}[/tex]
Therefore, [tex]\frac{16a^3bc^2}{abc}=16a^{3-1}b^{1-1}c^{2-1}=16a^2b^0c^1=16a^2c[/tex]
Hence, [tex]48a^3bc^2\div48a^3bc^2=16a^2c[/tex]
