contestada

a geologist had two rocks on a scale that weighed 2 1/2 pounds together rock A weighed a total of 1/7 of the weight how much did rock A weigh

Respuesta :

taskmasters
It is already given in the question that the combined weight of two rocks is  2 /1/2 pounds. The weight of rock A is also known and it is 1/7 of the total weight of the two rocks. This is enough to find the desired solution.
Now
Total weight of the two rocks = 2 1/2 pounds
                                               = 5/2 pounds
Then
Weight of Rock A = (5/2)/(1/7) pounds
                             = (5 * 7)/2 pounds
                             = 35/2 pounds
                             17 1/2 pounds
So Rock A weighs 17 1/2 pounds. This is the weight of Rock A and it is only required for this question. If you are eager to find the weight of rock B then you have to subtract the weight of Rock A form the total weight of the two rocks.

Answer:

Let A and B be the two rocks.

As per the statement: a geologist had two rocks on a scale that weighed 2 1/2 pounds together rock

⇒Total weight of rock ([tex]A+B [/tex]) = [tex] 2\frac{1}{2}[/tex] pounds

or

[tex]A+B= \frac{5}{2}[/tex]

Also, it is given A weighed a total of [tex]\frac{1}{7}[/tex] of the weight.

⇒ [tex]A = \frac{1}{7} \times (\text{Total weight})[/tex]

then;

[tex]A = \frac{1}{7} \times \frac{5}{2} = \frac{5}{14}[/tex]

Therefore, [tex]\frac{5}{14}[/tex] pounds did rock A weight.

Otras preguntas