Jane,Andre,and Maria pick apples. Andre picks three times as many pounds Maria. Jane picks two times pounds as Andre. The total weight of apples is 840 pounds. How many pounds of apples does Andre pick?

Respuesta :

Andre picks 252 pounds of apples.

Further explanation:

Jane, Andre and Maria pick apples such that the apples picked by Jane are denoted by J, the apples picked by Andre are denoted by A and the apples picked by Maria are denoted by M.

The total weight of apples is 840 pounds.

Therefore, this can be written as,

[tex]{\text{J + A + M}} = 840[/tex]                   ...... [tex](1)\\[/tex]

Andre picks three times as many pounds Maria then .[tex]{\text{A=3M}}[/tex].

Jane picks two times pounds as Andre then  .[tex]J = 2A[/tex].

Substitute 3M for A in the equation [tex]J = 2A[/tex] to obtain relation between J and M as,

[tex]\begin{aligned}{\text{J}}&={\text{2A}}\\&= {\text{2}}\cdot{\text{3M}}\\&={\text{6M}}\end{aligned}[/tex]

Now, substitute 3M for A and 6M for J in equation (1) then we get,

[tex]\begin{aligned} {\text{6M + 3M + M} &= 840}\\{\text{10M}& = 840}\\{\text{M}& = 84}\\\end {aligned}[/tex]

Therefore, Maria picks 84 pounds of apples.

Substitute the obtained value of [tex]M[/tex] as 84 in equation [tex]J = 2A[/tex] as,

[tex]\begin{gathered}{\text{J}}={\text{6}}\cdot {\text{84}}\\={\text{504}}\\\end{gathered}[/tex]

Therefore, Jane picks 504 pounds of apples.

Substitute the obtained value of [tex]M[/tex] as 84 in equation [tex]J = 6M[/tex]  as,

[tex]\begin{gathered}{\text{A}}={\text{3}}\cdot {\text{84}}\\={\text{252}}\\\end{gathered}[/tex]

Therefore, Andre picks 252 pounds of apples.

Thus, the total quantity that Andre picks is [tex]\boxed{{252}\text{ } \text{pounds}}[/tex].

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Linear equations

Keywords: Linear equations, function, sets, real numbers, ordinates, abscissa, interval, open interval, closed intervals, semi-closed intervals, semi-open intervals, graph.