your friend rent 10chairs and 2 tables for $300. another friend rent 8 chairs and 4 tables for $360 you want to rent 12 chairs and 3 tables how much do you expect to pay? ps I need it today
If x is chairs and y is tables then 10x+2y=300 8x+4y=360 solve for y and substitute to find x 10x+2y=300 2y=300 -10x y=150 -5x so put 150 -5x in for y in the other equation 8x+4(150-5x)=360 8x+600-20x=360 -12x=-240 x= $20 per chair
put that in for x in either equation to find y 10(20)+2y=300 2y=300-200 y=100/2 y= $50 per table
12 chairs and 3 tables would cost 12(20)+3(50)=240+150= $390
