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Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin foil that measures 5.70cm by 4.25cm and has a mass of 0.655g

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shinmin
To answer this question, you should first find the volume:7.28 g/ mL x .655 g / v = 0.08997 mL
volume = L x W x H, but thickness is the width. So rearranging the formula, the formula is v / l x h.
The thickness is found after dividing the volume by its length and width:
.08997 / (5.70) (4.25) = .004 cm is the thickness.

Answer:

The thickness of the piece of foil is [tex]3.71*10^{-3}cm[/tex]

Explanation:

Please see the figure below that represents the aluminum foil. The volume of the tin foil will be:

V = length * width * thickness

Now, the density of tin is given by the expression:

ρ = [tex]\frac{m}{V}[/tex]

where m is the mass of the tin and V is the volume of it.

From the expression for the density we have:

V = m/ρ

And replacing the expression for the Volume of the tin, we have:

length*width*thickness = m/ρ

so

thickness = m/(ρ*length*width)

And replacing the given values we have:

[tex]thickness=\frac{0.655g}{7.28\frac{g}{cm^{3}}*5.70cm*4.25cm}[/tex]

[tex]thickness=\frac{0.655g}{176,358\frac{g}{cm}}[/tex]

[tex]thickness=3.71*10^{-3}cm[/tex]

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