Respuesta :
The question for this problem would be the minimum headphone delay, in ms, that will cancel this noise.
The 200 Hz. period = (1/200) = 0.005 sec. It will need to be delayed by 1/2, so 0.005/2, that is = 0.0025 sec. So converting sec to ms, will give us the delay of:Delay = 2.5 ms.
The 200 Hz. period = (1/200) = 0.005 sec. It will need to be delayed by 1/2, so 0.005/2, that is = 0.0025 sec. So converting sec to ms, will give us the delay of:Delay = 2.5 ms.
The minimum headphone delay that will cancel the noise will be 2.5ms.
What is noise?
Noise simply means a form of pollution that's unpleasant and disruptive.
In this case, the minimum headphone delay that will cancel the noise will be calculated thus:
= 1/(200) × 1/2
= 0.0025 seconds
= 2.5m/s
In conclusion, the minimum headphone delay that will cancel the noise will be 2.5ms.
Learn more about noise on:
https://brainly.com/question/2278957