Respuesta :
Hey there,
Well, we would have to remember that the quadratic formula.
For [tex]ax^{2} +bx+c=0[/tex]
[tex]x \frac{-b+ \sqrt{ b^{2}-4ac } }{2a} [/tex]
So by clarifying this formula, we would understand alot more on
how to answer this question.
Your correct answer would be: . . .
0.25x2+0.8x−8=0
And I believe it would also be
−2x2+5x=7
Because they each illustrate the steps of the formula.
Hope this helps.
~Jurgen
Well, we would have to remember that the quadratic formula.
For [tex]ax^{2} +bx+c=0[/tex]
[tex]x \frac{-b+ \sqrt{ b^{2}-4ac } }{2a} [/tex]
So by clarifying this formula, we would understand alot more on
how to answer this question.
Your correct answer would be: . . .
0.25x2+0.8x−8=0
And I believe it would also be
−2x2+5x=7
Because they each illustrate the steps of the formula.
Hope this helps.
~Jurgen
Answer:
Option 1. [tex]0.25x^2+0.8x-8=0[/tex] and 4. [tex]-2x^2+5x=7[/tex] would be solved by the quadratic formula.
Step-by-step explanation:
We know the quadratic formula is used to find the roots of the equation, [tex]ax^{2}+bx+c=0[/tex].
Now, according to the options, we see that all four options are quadratic equations.
But, we will not use the quadratic formula for all.
Because,
[tex]-(x-3)(x+9)=0[/tex] can be easily solved by substituting each individual factor to 0.
[tex]3x^2=9[/tex] also can be easily solve by dividing both sides by 3 and taking square root.
Thus, the only options which will require to the quadratic formula are,
[tex]0.25x^2+0.8x-8=0[/tex]
[tex]-2x^2+5x=7[/tex]
Hence, option 1 and 4 would be solved by the quadratic formula.