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An isosceles trapezoid has a height of 6. The sum of the trapezoid's bases is 14. Find the area of the trapezoid. Type a numerical answer in the space provided. Do not include units or spaces in your answer.

Respuesta :

hisroyal1
The are of a trapezoid is solved using the formula [(a + b)/2]·h

Where a + b is the sum of the bases
h is the beight of the trapezoid

Given,
Sum of the bases, a + b = 14
Height, h = 6

Substituting these values in the formula [(a + b)/2]·h
⇒ [14/2]·6
= 7 * 6
= 42

The area of the trapezoid is 42
saadhussain514

Answer:

area=42

Explanation:

Area of Trapezoid

[(a+b)/2]h

a + b = 14

, h = 6

[14/2]*6

= 42