Respuesta :
We are given
[tex] -3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-........?........ [/tex]
Firstly, we will simplify left side
and then we can compare it with right side
Left side:
[tex] -3y(5y^3+11y^2-y+8) [/tex]
We can distribute -3y
[tex] =-3y*5y^3+-3y*11y^2--3y*y+-3y*8 [/tex]
now, we can simplify it
[tex] =-15y^4-33y^3+3y^2-24y [/tex]
now, we can compare it with right side
we can see that only last term is missing
so, there should be -24y in last term
so, we get
[tex] -3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-24y [/tex].................Answer
