Respuesta :

Hello there!
Find the last common denominator of the following rational expression 1/x-5 , x+3/x^2-10x+25, 7x/x^2-25

Find the LCD.
[tex] x^{2} (x-5)(x+5)[/tex]

Answer: [tex] x^{2} (x-5)(x+5)[/tex]

The least common denominator of the given rational expressions is [tex](x+5)(x-5)^{2}[/tex].

What is the least common denominator?

"The least common denominator is the smallest number of all the common multiples of the denominators when 2 or more fractions are given."

The given expressions are:

1. [tex]\frac{1}{x-5}[/tex]

2. [tex]\frac{x+3}{x^{2} -10x+25} = \frac{x+3}{(x-5)^2}[/tex]

3. [tex]\frac{7x}{x^{2} -25} = \frac{7x}{(x+5)(x-5)}[/tex]

Therefore,  the least common denominator is

[tex](x+5)(x-5)^{2} = (x+5)(x-5)^{2}[/tex]

Learn more about least common denominator here: https://brainly.com/question/8393834

#SPJ2