We are given
ABCD is a rhombus
so, firstly , we need to draw diagram
we can see that
diagonal bisects angle
so,
m∠DAB=2*m∠DAC
now, we can plug values
[tex] 11x-3=2(4x+9) [/tex]
now, we can solve for x
[tex] 11x-3=2*4x+2*9 [/tex]
[tex] 11x-3=8x+18 [/tex]
[tex] 11x-3+3=8x+18+3 [/tex]
[tex] 11x=8x+21 [/tex]
subtract both sides by 8x
[tex] 11x-8x=8x-8x+21 [/tex]
[tex] 3x=21 [/tex]
Divide both sides by 3
we get
[tex] x=7 [/tex]...............Answer
