Respuesta :

abscisa15

[tex]\it 3x+2y=14 \\ 5x-2y=18 \\ ------\\ 8x \ \ \ \ \ \ \ =32 \Rightarrow x = 32:8\Rightarrow x=4 \ \ \ (*)[/tex]

[tex]\it 3x+2y=14 \stackrel{(*)}{\Longrightarrow} 3\cdot4+2y=14 \Rightarrow 12+2y=14 \Rightarrow 2y=14-12\Rightarrow \\\;\\ \Rightarrow 2y=2 \Rightarrow y=2:2 \Rightarrow y=1[/tex]

Therefore, the solution is:  x = 4,  y=1.
First you multiply both equations by 5 and 3
Then you take away both the equations form one another
Next you divide by 4 to get y on its own
This gives you y - which is 4

Then you choose one equation from your question. I chose 3x + 2y = 14 because it looks easier
Input your y value (that you just worked out before) into the y on this equation
Get x on its own by minusing 8 then dividing by 3
This gives you x - which is 2


Ive put a picture incase you still do not understand
Ver imagen CometZ

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