Quadrilateral ABCD has vertices A(0,0), B(2,0), C(3,4), and D(0,4). Find the vertices of quadrilateral A'B'C'D' after a translation of 4 units right and 2 units down.

Respuesta :

You will be adding 4 to the x-axis because it is positive, to go left you would subtract. Then you would be subtracting 2 to the y axis because you are going down. To go up you would add. 

A(0,0)
+4,-2
A'(4,-2)


B(2,0)
+ 4,-2
B'(6,-2)

C(3,4)
+4,-2
C'( 7,2)

D(0,4)
+4,-2 
D'(4,2)



Then the coordinate of the quadrilateral A'B'C'D' will be A'(4, -2), B'(6, -2), C'(7, 2), and D'(4, 2).

What is a transformation of a point?

A spatial transformation is each mapping of feature space to itself and it maintains some spatial correlation between figures.

Quadrilateral ABCD has vertices A(0,0), B(2,0), C(3,4), and D(0,4).

Then the vertices of quadrilateral A'B'C'D' after a translation of 4 units right and 2 units down. Then the transformation rule will be

(x', y') ⇒ (x + 4, y - 2)

Then the coordinate of the quadrilateral A'B'C'D' will be

A' (0 + 4, 0 - 2) = A'(4, -2)

B' (2 + 4, 0 - 2) = B'(6, -2)

C' (3 + 4, 4 - 2) = C'(7, 2)

D' (0 + 4, 4 - 2) = D'(4, 2)

Then the coordinate of the quadrilateral A'B'C'D' will be A'(4, -2), B'(6, -2), C'(7, 2), and D'(4, 2).

More about the transformation of a point link is given below.

https://brainly.com/question/27224339

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