If we take the number of Zebras to be x and that of peacocks to be y
Then x + y = 14
A zebra has 4 legs while a peacock has 2 legs,
Therefore the total number of legs will be 4x + 2y which is equal to 36 .
Therefore, we have two equations
x + y = 14
4x + 2y = 36 solving them simultaneously using elimination
4x +2y = 36
2x + 2y = 28 ( multiplying the first equation by 2 to eliminate y)
2x = 8 ( subtracting the equations)
x = 4
y = 14 -(4)
= 10
Therefore, there are 4 zebras and 10 peacocks in the zoo
