Alright, lets get started.
The given function is [tex] x^2 - x - 72 [/tex].
For finding its zeros, we need to first factor this function and then set it equal to zero.
[tex] x^2 - x -72 [/tex]
[tex] (x-9)(x+8)= 0 [/tex]
[tex] (x-9) = 0 [/tex]
[tex] x = 9 [/tex]
[tex] (x+8) = 0 [/tex]
[tex] x = -8 [/tex]
Hence the zeros are 9 and -8 of given function. : Answer
Hope it will help :)
