Respuesta :
3x - 4y = 12 ----- (1)
x + 4y = 20 ------ (2)
equation (2) x 3:
3x + 12y = 60 ---(2a)
(2a) - (1):
12y - (-4y) = 60 - 12
12y + 4y = 48
16y = 48
y = 3 ---- sub into equation (2)
x + 4(3) = 20
x + 12 = 20
x = 8
Ans: x = 8 and y = 3 (True)
x + 4y = 20 ------ (2)
equation (2) x 3:
3x + 12y = 60 ---(2a)
(2a) - (1):
12y - (-4y) = 60 - 12
12y + 4y = 48
16y = 48
y = 3 ---- sub into equation (2)
x + 4(3) = 20
x + 12 = 20
x = 8
Ans: x = 8 and y = 3 (True)
Both equations have a 4y term, so we can use elimination to easily solve the system.
3x - 4y = 12
x + 4y = 20
----------------
4x + 0y = 32
Now we can solve for x.
4x = 32
x = 8
Now we plug 8 in for x in either of the original equations to find y.
3(8) - 4y = 12
24 - 4y = 12
-4y = -12
y = 3
So yes, it is true that x = 8 and y = 3.
Hope this helps :)
3x - 4y = 12
x + 4y = 20
----------------
4x + 0y = 32
Now we can solve for x.
4x = 32
x = 8
Now we plug 8 in for x in either of the original equations to find y.
3(8) - 4y = 12
24 - 4y = 12
-4y = -12
y = 3
So yes, it is true that x = 8 and y = 3.
Hope this helps :)