The density of liquid mercury is 13.69 g/cm 3 . how many atoms of mercury are in a 17 ml sample? use "e" for "×10" and report the answer to at least 4 significant figures.

step one; calculate mass
Mass=density x volume
1ml=1cm^3
13.69g/cm^3 x 17 cm^3=232.73g

step 2; calculate the number of moles of mercury
(232.73g/200.59g/mol)(molar mass of mercury= 1.1602moles

by use of avogdros law
1moles =6.023E23 atoms
what about 1.1602moles
=1.1602 x 6.023E23= 6.988E23atoms

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lhabdulsamirahmed lhabdulsamirahmed · Answer 2 · 2022-02-15T12:02:40+01:00

17ml sample of mercury contain 6.988e23 atoms

Data;

Density = 13.69 g/cm^3
Volume = 17ml
mass = ?

Density of Mercury

The density of a substance can be calculated as the ratio between the mass of that substance and it's volume.

[tex]\rho= \frac{mass}{volume}[/tex]

Let's substitute the values and solve for the mass

[tex]\rho = \frac{mass}{volume} \\13.69 = \frac{x}{17ml}\\ mass = 232.73g[/tex]

NB; 1 ml = 1cm^3

From here, we can apply Avogadro's number to calculate the number of atoms.

Molar mass of Mercury = 200.59g/mol

Molar mass = Avogadro's Number

[tex]200.59g = 6.023*10^2^3atoms\\232.73g = x atoms\\x = \frac{232.73*6.023*10^2^3}{200.59}\\x = 6.988*10^2^3atom\\x = 6.988 e23 atoms[/tex]

From the calculations above, 17ml sample of mercury contain 6.988e23 atoms

Learn more on density and Avogadro's number here;

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