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Tommy was walking at a rate of 4 miles per hour at noon and at 12:30 pm he was walking at a brisk rate of 6 miles per hour.Two hours later tommy was walking at a leisurely rate of 2 miles per hour. What was Tommy’s acceleration between noon and 12:30 pm?

Respuesta :

Placed
Tommy had more acceleration between 12:30 and 2:30 pm

Answer:

Tommy’s acceleration between noon and 12:30 pm is 4 miles/hr².

Explanation:

Given that,

Initial velocity = 4 miles/hr

Final velocity = 6 miles/hr

Time t = 30 minutes

Acceleration :

Acceleration is the rate of change of the velocity of the particle.

We need to calculate the Tommy’s acceleration between noon and 12:30 pm

Using equation of motion

[tex]v = u+at[/tex]

[tex]a=\dfrac{v-u}{t}[/tex]

Where, v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the formula

[tex]a=\dfrac{2(6-4)}{1}[/tex]

[tex]a=4\ miles/hr^2[/tex]

Hence, Tommy’s acceleration between noon and 12:30 pm is 4 miles/hr².

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