Answer:
The object is at a height of 0.0335 m
Explanation:
First let's see what is the formula of gravitational potential energy
[tex]E_p=m.g.h[/tex]
m= mass of the object
g= gravity (the value of gravity is a constant. Its value is approximately [tex]9.8m/s^2[/tex])
h= height at which the object is in relation to zero
To calculate the height at which the object is enclosed, we clear the h of the formula
[tex]E_p= m.g.h\\\frac{E_p}{m.g}=h[/tex]
Now we substitute the data in the formula
[tex]\frac{E_p}{m.g}=h\\\frac{400J}{1220Kg.9.8\frac{m}{s^2} }= h\\0.0335m=h[/tex]
The object is at a height of 0.0335 m
