Respuesta :
A) All of your answers will come from a combination of the periodic table and a little bit of math.
To calculate #of moles in NaCl, you need to look at their masses on the periodic table
Na ~ 23g
Cl ~ 35.5g
So, if one mol is Na is 23g and one mol of Cl is 35.5g, then the molar mass of NaCl must be Na+Cl
Na+Cl = 78.5g
1 mol of NaCl is 78.5g so if you have less than that in grams, you have <1 mol
To get the exact amount, you’ll do a conversion
30.22g of NaCl / 78.5g NaCl is .38 mols
B) is a confusing question. It could technically be 23g and 35.5g; however, i suspect, that you could say that because NaCl is 1 to 1, that each one gets 50% of the compound...meaning each one would be .19 mols...or you could try doing conversions like the one above, but with the individual atoms.
C) do a conversion with Avogadro’s number 6.02 x 10^23 g/mol
Sorry, my physics class is about to start. Hope this helped.
To calculate #of moles in NaCl, you need to look at their masses on the periodic table
Na ~ 23g
Cl ~ 35.5g
So, if one mol is Na is 23g and one mol of Cl is 35.5g, then the molar mass of NaCl must be Na+Cl
Na+Cl = 78.5g
1 mol of NaCl is 78.5g so if you have less than that in grams, you have <1 mol
To get the exact amount, you’ll do a conversion
30.22g of NaCl / 78.5g NaCl is .38 mols
B) is a confusing question. It could technically be 23g and 35.5g; however, i suspect, that you could say that because NaCl is 1 to 1, that each one gets 50% of the compound...meaning each one would be .19 mols...or you could try doing conversions like the one above, but with the individual atoms.
C) do a conversion with Avogadro’s number 6.02 x 10^23 g/mol
Sorry, my physics class is about to start. Hope this helped.