HELP FAST PLEASE!!!!!


Sandra wants to evaluate 2cot(-9pi/2). Herwork is shown below. What did she do wrong?
2cot(-9pi/2)=2cot(9pi/2)
2cot(-9pi/2)=2cot(pi/2)
2cot(-9pi/2)=2(0)
2cot(-9pi/2)=0

Respuesta :

Alright, lets get started.

The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.

[tex] 2 cot(\frac{-9\pi}{2}) = 2 cot(\frac{9\pi}{2}) [/tex] Incorrect step

Because as per even/odd identity,

Cot (-Θ) = - cot (Θ)

Hence

[tex] 2 cot (\frac{-9\pi}{2}) = - 2 cot (\frac{9\pi}{2}) [/tex]

Now,

It could be written as

[tex] -2 cot (\frac{9\pi}{2}) = -2 cot (\frac{\pi}{2}) [/tex]


[tex] -2 * 0 [/tex]

0

Hence the answer is 0. : Answer

Hope it will help :)