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If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c = 3x108 m/s
3.92 x 104
3.92 x 1010
5.07 x 107
5.07 x 1010
6.26 x 10-24

Respuesta :

kenmyna
E(energy)  is released  is calculated  as
E=MC^2
E=  energy  in   joules\
M=mass  in  Kg
C=is  the   speed  of  light

energy  is  therefore  calculated  as
((5.63 x  10^-7) {(3  x 10^8)^2)}=5.067   x  10 ^10 j( answer  D)

Answer:

[tex] 5.07\times 10^{10}[/tex] Joules of energy would be released.

Explanation:

Loss of mass in nuclear reaction= m = [tex]5.63\times 10{^-7}kg[/tex]

Speed of light = [tex] c= 3\times 10^{8} m/s[/tex]

Energy released = E

According to Einstein equation:

[tex]E=mc^2[/tex]

[tex]E=5.63\times 10{^-7}kg\times 3\times 10^{8} m/s=5.07\times 10^{10}J[/tex]

[tex] 5.07\times 10^{10}[/tex] Joules of energy would be released.