Respuesta :

First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
[tex]Co=58.933[/tex]
[tex]Cl=35.45[/tex]
[tex]H=1.008[/tex]
[tex]O=15.999[/tex]

Now, let's find the mass of each compound.

[tex]CoCl_2=58.933+2(35.45)=129.833[/tex]
[tex]H_2O=2(1.008)+15.999=18.015[/tex]

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

[tex]6(18.015)=108.09[/tex]
[tex]129.833+108.09=237.923[/tex]

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

[tex]\dfrac{108.09}{237.923}[/tex]

[tex]\approx0.45431[/tex]

Turn that into a percentage and you get 45.431%.
Hope this helps! :)

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