Respuesta :
To determine if the rectangle triangles shown in the diagram are congruent, we must see if they comply with the following conditions:
1. The legs of a right triangle must be congruent to the corresponding legs of the other triangle.
2. The hypotenuse and acute angle of one of the right triangles must be congruent to the hypotenuse and the acute angle of the other right triangle.
3. A leg and the acute angle of one of them must be congruent to one leg and to the corresponding acute angle of the other right triangle.
4. The hypotenuse and a the leg of one of the triangles must be congruent to the hypotenuse and the corresponding leg of the other triangle.
When we observe the diagram attached to the problem, we can conclude that both triangles comply with the conditions mentioned before.Then, FGH and JKL are congruent.
Answer: True
1. The legs of a right triangle must be congruent to the corresponding legs of the other triangle.
2. The hypotenuse and acute angle of one of the right triangles must be congruent to the hypotenuse and the acute angle of the other right triangle.
3. A leg and the acute angle of one of them must be congruent to one leg and to the corresponding acute angle of the other right triangle.
4. The hypotenuse and a the leg of one of the triangles must be congruent to the hypotenuse and the corresponding leg of the other triangle.
When we observe the diagram attached to the problem, we can conclude that both triangles comply with the conditions mentioned before.Then, FGH and JKL are congruent.
Answer: True
Answer:
A) True
Step-by-step explanation:
In the given right angled ΔFGH and ΔJKL
GF ≅ KJ ( one side of both right angle triangles)
∠F≅ ∠J (right angle)
FH ≅ JL (other side of both right angle triangles )
Then ,
we can say that GH ≅ KL (hypotenuse of both right angle triangles)
Now from RHS congruence rule → in two right triangles the hypotenuse and one side of one triangle are equal to the hypotenuse and one side of the other triangle ,then the two triangles are congruent.
Hence,
ΔFGH ≅ ΔJKL
So, option A) True