Respuesta :
So we are given a system:
[tex]3x-2y+3z=0\\ -3x - 5y - 5z= -21[/tex]
Substitute x = 2 we get the system:
[tex]-2y+3z=-6\\ - 5y - 5z= -15[/tex]
Multiply the first equation by -5 and the second by 2 we get the system:
[tex]10y-15z=30\\ - 10y - 10z= -30[/tex]
Adding the two equations we get :
[tex]-25z=0\text{ then}z=0.[/tex]
We find the value of y by using any of the other equations like this:
[tex]-2y=-6\\y=3.[/tex]
Final solution:
[tex]z=0,y=3[/tex]
[tex]3x-2y+3z=0\\ -3x - 5y - 5z= -21[/tex]
Substitute x = 2 we get the system:
[tex]-2y+3z=-6\\ - 5y - 5z= -15[/tex]
Multiply the first equation by -5 and the second by 2 we get the system:
[tex]10y-15z=30\\ - 10y - 10z= -30[/tex]
Adding the two equations we get :
[tex]-25z=0\text{ then}z=0.[/tex]
We find the value of y by using any of the other equations like this:
[tex]-2y=-6\\y=3.[/tex]
Final solution:
[tex]z=0,y=3[/tex]
