The Neperian Logarithms have the number "e" as the base and are symbolized with the abbreviation "ln".
To evaluate y=ln(x − 2) for the values of x (x=3, x=4 and x=6), you must substitute those values in the function, as below:
1. x=3
y=ln(x−2)
y=ln (3-2)
y=ln(1)
y=0
2. x=4
y=ln(x−2)
y=ln(4−2)
y=ln(2)
y≈0.693
3. x=6
y=ln(x− 2)
y=ln(6−2)
y=ln(4)
y≈1.386
