4" x 2500 ft², namely 4 ft x 2500 ft², will just be 4*2500*ft*ft², or 10000 ft³.
[tex]\bf \begin{array}{ll}
yd&3ft\\\\
(yd)^2&(3ft)^2\\
&(3^2ft^2)\\
&9ft^2\\\\
(yd)^3&(3ft)^3\\
&(3^3ft^3)\\
&27ft^3
\end{array}[/tex]
since there are 27 ft³ in 1 yd³, then how many yd³ are there in 10000 ft³?
10000/27, that many yd³.
