We will evaluate each function separately in the given interval: 0 <x <π f (x) = sin x f (0) = sin 0 = 0 f (π) = sin π = 0
f (x) = cos x f (0) = cos 0 = 1 f (π) = cos π = -1
f (x) = cot x f (0) = cot 0 = Cos0 / sin0 = 1/0 = inf f (π) = cot π = Cosπ / sinπ = -1 / 0 = -inf We can observe that the function f (x) = cot x tends to infinity when it approaches zero.
f (x) = sec x f (π / 2) = sec π / 2 = 1 / cos π / 2 = 1/0 = inf We can observe that this function has values that tend towards infinity when it approaches π / 2
answer: this function has values greater than 1 in 0 <x <π f (x) = sec x
