Let x be the number of hours spent in dog-walking
Let y be the number of hours spend in car washing.
The maximum number of hours at work in a week is 20.
Therefore x + y <=20
Salary for dog-walking job =$7.50/ hour
Salary for car washing job=$6/ hour
Total salary in a week earned through dog-walking job =7.50x
Total salary in a week earned through car washing job=6y
Least amount to be earned in a week =$92
Therefore, 7.50x +6y>=92
The required inequalities are
x+y<=20; 7.50x+6y>=92
2.
Let x be the number of soil bags
Let y be the number of plants
Cost per soil bag = $4
Cost per plant =$10
Minimum number of plants she wants to buy =5
Therefore, y>=5
Maximum amount she can spent =$100
Therefore 4x+10y<=100
The required inequalities are
y>=5; 4x+10y<=100
