[tex]\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &40\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
t=\textit{elapsed time}\to &12\\
\end{cases}
\\\\\\
A=40(1+0.05)^{12}\implies A=40(1.05)^{12}\implies A\approx 71.8342530[/tex]