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A chemist prepares two acid solutions. Solution 1: 3 parts sulfuric acid to 7 parts water. Solution 2: 4 parts sulfuric acid to 9 parts water.

Questions:

A.) Use a ratio table to determine which solution is more acidic.

B.) Use a graph to determine which solution is more acidic.

C.) Which method do you prefer? Explain.

Respuesta :

henaadlakhap3tm5j
A) Solution 2 is more acidic.
Solution 1= 3:7 = 27:63
Solution 2= 4:9 = 28:63
Sorry I can't present the answers next two parts rn.
isyllus

Answer:

A) solution 2 is more acidic than solution 1

B) Graph in attachment

C) Ratio method prefer

Step-by-step explanation:

A chemist prepares two acid solutions.

Solution 1: 3 parts sulfuric acid to 7 parts water

Ratio of sulphur to water [tex]=\dfrac{3}{7}[/tex]

Solution 2: 4 parts sulfuric acid to 9 parts water

Ratio of sulphur to water [tex]=\dfrac{4}{9}[/tex]

Part A: Using ratio to find the more acidic

First we make same denominator

Solution 1: [tex]\Rightarrow \dfrac{3\times 9}{7\times 9}=\dfrac{27}{63}[/tex]

Solution 2: [tex]\Rightarrow \dfrac{4\times 7}{9\times 7}=\dfrac{28}{63}[/tex]

As 28 > 27

Therefore, solution 2 is more acidic than solution 1

Part B: Let y amount of sulfuric acid mix with x amount of water.

Equation of solution 1: [tex]y=\dfrac{3}{7}x[/tex]

Equation of solution 2: [tex]y=\dfrac{4}{9}x[/tex]

Please find attachment for graph.

Part C: part A method is more prefer to find more acidic. Because it gives actual amount of acidic.

Ver imagen isyllus