Respuesta :
Answer:
h(t) = -16t²+20t+4
Step-by-step explanation:
These equations are of the form
h(t) = -16t²+v₀t+h₀, where -16 is 1/2 the constant due to gravity, v₀ is the initial velocity and h₀ is the initial height.
Our initial velocity is 20 and our initial height is 4; this gives us
h(t) = -16t²+20t+4
Answer:
[tex]h(t) = -16t^2+20t+4[/tex]
Step-by-step explanation:
The general form of equation for height
[tex]h(t) = -16t^2+v_0t+h_0[/tex]
Where -16 is 1/2 the constant due to gravity
v₀ is the initial velocity
h₀ is the initial height.
Now we are given
Min’s little brother throws a baseball from a height of 4 feet with an initial vertical velocity of 20 feet per second.
So, v₀ = initial velocity = 20 ft/sec
h₀ = initial height= 4 feet
substitute the values in the equation:
[tex]h(t) = -16t^2+20t+4[/tex]
Hence t polynomial models the height of this ball, in feet is [tex]h(t) = -16t^2+20t+4[/tex]
