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A baseball is hit with a bat and, as a result, its direction is completely reversed and its speed is doubled. If the actual contact with the bat lasts 0.73 s, what is the ratio of the acceleration to the original velocity?

Respuesta :

F = ma = mv/t = m×(2v)/0.73 = 2.73973mv

1:2.73973

Answer:

ratio aceleration to velocity is  a/vo =  -4

Explanation:

This is an impulse problem since the bat hits the ball and this changes its speed

       I = Δp

If we look for the average strength

     F t = m vf -mvo

They say that  vf = -2vo

Calculated

      F = [m (-2vo) -mvo] / t

      F = - m 3 vo / t

having the average force, we can look for acceleration with Newton's second law

      F = m a

      a = F / m

      a = (- 3m vo / t) / m

      a = -3 vo / t

They ask us for the relation of the acceleration with the initial velocity

     a / vo = - 3 / t

     a / vo = -3 / 0.73

    a / vo =  -4

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