Answer:
C. 6.59 KJ
Explanation:
To solve this question, we will use the following rule:
q = mCΔT
where:
q us the amount of heat gained that we want to calculate
m is the mass of the water = 225 grams
C is the specific heat capacity of the water = 4.184 J / g - C
ΔT is the change in temperature = Tfinal - Tinitial = 32 - 25 = 7 degrees
Substitute with the givens in the above equation to get the amount of heat gained as follows:
q = mCΔT
q = 225 * 4.184 * 7 = 6589.8 Joules = 6.5898 KJ which is approximately choice C.
Hope this helps :)
