Respuesta :

vertical asymptotes appear at any n*pi with n as some integer
in your case x=-1*pi (the others are fractions not integers), so the first option

The asymptote of the function [tex]y = \csc \left( x \right)[/tex] is [tex]\boxed{x =  - \pi }.[/tex]

Further explanation:

Given:

The function is [tex]y = \csc \left( x \right)[/tex]

The options are as follows,

(a).[tex]x =  - \pi[/tex]

(b).[tex]x =- \dfrac{\pi }{3}[/tex]

(c).[tex]x =\dfrac{\pi }{4}[/tex]

(d).[tex]x=\dfrac{\pi }{2}[/tex]

Explanation:

The vertical asymptote is point at which the function is not defined.

The value of [tex]y = \csc \left( x \right)[/tex] can be written as follows,

[tex]y=\csc\left( x \right)=\dfrac{1}{{\sin \left( x \right)}}[/tex]

The function is not defined if the value of \sin \left( x \right) = 0.

The value of [tex]\sin \left( x \right) = 0 at x = 0 or x = n\pi.[/tex]

The value of [tex]y = \dfrac{1}{{\sin \left( x \right)}}[/tex] is not defined for [tex]x =  - \pi.[/tex]

The asymptote of the function [tex]y = \csc \left( x \right)[/tex] is [tex]\boxed{x =  - \pi }.[/tex]

Option (a) is correct as the asymptote of the function is [tex]x =  - \pi.[/tex]

Option (b) is not correct as the asymptote of the function is [tex]x =  - \pi.[/tex]

Option (c) is not correct as the asymptote of the function is [tex]x =  - \pi.[/tex]

Option (d) is not correct as the asymptote of the function is [tex]x =  - \pi.[/tex]

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function https://brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Trigonometry

Keywords: asymptote, y=cos(x), vertical asymptote, horizontal asymptote.