Respuesta :
Both r(x) and c(x) are in hundreds of dollars. The difference r(x) -c(x) is the excess of revenue over cost, hence profit. (r -c)(3) is the profit in hundreds of dollars when the store has been open 3 months. (r -c)(3) = 34, so the model says the store has a profit of 3400 dollars after being open 3 months.
Selection C is appropriate.
Selection C is appropriate.

(r-c)(3) means that you will simply plug in the value 3 as x in the functions r(x) and c(x) and take the difference of both.
Solving for the value of the functions we'll get:
[tex]r(3)= (3)^{2}+5(3)+14=9+15+14=38 [/tex]
[tex]c(3)= (3)^{2}-3(3)+14=9-9+4=4 [/tex]
[tex](r-c)(3)=38-4=34 [/tex]
Since the value is positive, we can say that the store will profit in its third month. Knowing that r(x) and c(x) is measured in hundreds of dollars, we can also say that the profit will be $3400.
ANSWER: C. The new store will have a profit of $3400 after its third month in business.
Solving for the value of the functions we'll get:
[tex]r(3)= (3)^{2}+5(3)+14=9+15+14=38 [/tex]
[tex]c(3)= (3)^{2}-3(3)+14=9-9+4=4 [/tex]
[tex](r-c)(3)=38-4=34 [/tex]
Since the value is positive, we can say that the store will profit in its third month. Knowing that r(x) and c(x) is measured in hundreds of dollars, we can also say that the profit will be $3400.
ANSWER: C. The new store will have a profit of $3400 after its third month in business.