If you have 0.5 L of air in a rigid, sealed container at a pressure of 203 kPA and a temp of 203. You heat the contain to 273 K. What is the final pressure of the air?
Volume remains constant: P1 x T2 = P2 x T1. Pressure increases in direct proportion to absolute temperature increase. 203kPa x 273K = P2 x 203K = P2 x 55,419. P2 = 55,419 / 203 = 273kPa final pressure.
