Answer:
[tex]I=5.48\times 10^{-11}\ A[/tex]
Explanation:
It is given that,
Number of Na⁺ ion, n = 1200 C
So, total charge, [tex]q=1200\times 1.6\times 10^{-19}\ C[/tex]
Time taken to flow the charges, t = 3.5 μs = 3.5 × 10⁻⁶ s
Electric current is defined as the ratio of electric charge per unit time.
[tex]I=\dfrac{q}{t}[/tex]
[tex]I=\dfrac{1200\times 1.6\times 10^{-19}\ C}{3.5\times 10^{-6}\ s}[/tex]
[tex]I=\dfrac{1200\ C}{3.5\times 10^{-6}\ s}[/tex]
[tex]I=5.48\times 10^{-11}\ A[/tex]
So, the current flowing in the circuit is [tex]5.48\times 10^{-11}\ A[/tex]
