Respuesta :
T = 273 K, P = 2.00 atm: V = 11.2 L
T = 546 K, P = 1.00 atm: V = 44.8 L
T = 409.5 K, P = 1.50 atm: V = 22.4 L
The ideal gas law is:
PV = nRT
where
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = absolute temperature
There's a lot of different values for R depending upon the units involved.
Given that we're using liters and atm, the constant I'll use is 0.082057338
L*atm/(K*mol)
Let's solve for volume
PV = nRT
V = nRT/P
Let's substitute the known values for n and R.
V = nRT/P
V = 1.00 mol * 0.082057338 L*atm/(K*mol) * T/P
V = 0.082057338 L*atm/K * T/P
Now simply substitute the given values and calculate. I'll do the full calculation for the 1st problem, and then simply give the answers for the remaining 2 problems.
T = 273 K, P = 2.00 atm: V = 11.2 L
V = 0.082057338 L*atm/K * T/P
V = 0.082057338 L*atm/K * 273 K/2.00 atm
V = 22.40165327 L*atm /2.00 atm
V = 11.20082664 L
Rounding to 3 significant figures gives 11.2 L.
T = 546 K, P = 1.00 atm: V = 44.8 L
T = 409.5 K, P = 1.50 atm: V = 22.4 L
T = 546 K, P = 1.00 atm: V = 44.8 L
T = 409.5 K, P = 1.50 atm: V = 22.4 L
The ideal gas law is:
PV = nRT
where
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = absolute temperature
There's a lot of different values for R depending upon the units involved.
Given that we're using liters and atm, the constant I'll use is 0.082057338
L*atm/(K*mol)
Let's solve for volume
PV = nRT
V = nRT/P
Let's substitute the known values for n and R.
V = nRT/P
V = 1.00 mol * 0.082057338 L*atm/(K*mol) * T/P
V = 0.082057338 L*atm/K * T/P
Now simply substitute the given values and calculate. I'll do the full calculation for the 1st problem, and then simply give the answers for the remaining 2 problems.
T = 273 K, P = 2.00 atm: V = 11.2 L
V = 0.082057338 L*atm/K * T/P
V = 0.082057338 L*atm/K * 273 K/2.00 atm
V = 22.40165327 L*atm /2.00 atm
V = 11.20082664 L
Rounding to 3 significant figures gives 11.2 L.
T = 546 K, P = 1.00 atm: V = 44.8 L
T = 409.5 K, P = 1.50 atm: V = 22.4 L
The volume of 1 mole of a gas under the given conditions are 11.193L, 44.77L and 22.386L respectively.
How do we calculate the volume?
Volume of any gas will be calculated by uisng an ideal gas equation as:
PV = nRT, where
P = pressure of gas
V = volume of gas
n = number of moles of gas = 1mol
R = ideal gas constant = 0.082 L.atm/K.mol
T = absolute temperature
- Volume of gas at 273 K temperature and 2 atm pressure will be:
V = (1)(0.082)(273)/(2) = 11.193 L
- Volume of gas at 546 K temperature and 1 atm pressure will be:
V = (1)(0.082)(546)/(1) = 44.77 L
- Volume of gas at 409.5 K temperature and 1.50 atm pressure will be:
V = (1)(0.082)(409.5)/(1.5) = 22.386 L
Hence the required volume of given gas are 11.193L, 44.77L and 22.386L.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/555495
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